Answer:
Here, \[\text{u}=0,\text{s}=\text{x},\text{ t}=\text{t}\].
Using the relation, \[\text{s}=\text{ut}+\frac{1}{2}\text{a}{{\text{t}}^{\text{2}}}\],
we have \[\text{x}=0+\frac{1}{2}\text{a}{{\text{t}}^{\text{2}}}\] ...(i)
Let the body travel a distance y in next t seconds. The
total distance travelled in \[\text{t }+\text{ t }=\text{2t}\] seconds will be\[~(\text{x}+\text{
y})\].So
\[\left(
\text{x }+\text{ y} \right)\text{ }=\frac{1}{2}\text{a}{{\left( \text{2t}
\right)}^{\text{2}}}=\frac{1}{2}~\text{a }\times \text{
4}{{\text{t}}^{\text{2}}}\] ...(ii)
Dividing (ii) by (i), we get, \[\frac{x+y}{x}=4\]
or \[\text{y}=\text{3x}\]
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