question_answer

An object is in uniform motion along a straight line. What will be position-time graph for the motion of the object if (a) \[{{\text{x}}_{\text{0}}}=+\text{ve},\upsilon =+\text{ve}\] (b) \[{{\text{x}}_{\text{0}}}=+\text{ve},\upsilon =-\text{ve}\]          (c) \[{{\text{x}}_{\text{0}}}=-\text{ve},\upsilon =+\text{ve}\] and (d) both \[{{\text{x}}_{\text{0}}}\] and \[\upsilon \] are negative? The letters \[{{\text{x}}_{\text{0}}}\] and v represent position of the object at time \[t=0\] and uniform velocity of the object respectively.

Answer:

                The position of the object at any time t while moving with uniform velocity along a straight line is given by, \[\text{x }={{\text{x}}_{\text{0}}}+\upsilon \text{t}\] (a) If \[{{\text{x}}_{\text{0}}}=+\text{ve}\] and \[\upsilon =+\text{ve}\], position - time graph will be as shown in Fig. 2(a).23 (a) (b) If \[{{x}_{0}}=+ve\]and \[\upsilon =-\text{ve}\], the position - time graph will be as shown in Fig 2(a).23 (b). (c) If \[{{x}_{0}}=-\text{ve}\] and \[\upsilon =+\text{ve}\], the position - time graph will be as shown in Fig 2(a).23 (c). (d) If both \[{{x}_{0}}\] and \[\upsilon \] are, negative, the position - time graph will be as shown in Fig. 2(a).23 (d).                 (a)    (b)    (c)     (d)