question_answer

A block of mass 1 kg lies on horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the block is \[5\,m{{s}^{-2}}\], calculate the frictional force acting on the block.

Answer:

                Limiting force of friction \[F=\mu R=\mu mg\,=0.6\,\times 1\times 9.8=5.88\,N\] Applied force, \[F'=ma\,=1\times 5=5N\] As \[F'<F\], the block would not move. Force of friction = applied force = 5 N.