question_answer

A body of 2 kg is suspended on a spring balance hung vertically in a lift. If the lift is falling downward under acceleration due to gravity g, then what will be the reading of the balance? If going upward with the same acceleration, then?

Answer:

                Reading of the balance = apparent weight W' = m (g - a) = m (g - g) = zero., If lift is going upwards with same ace ; W' = m (g + a) = m (g + g) = 2 m g = 4 kg