Answer:
\[x=\text{6}\text{.75}\times
\text{1}{{0}^{\text{3}}},\text{y}=\text{4}\text{.52}\times
\text{1}{{0}^{\text{2}}}\text{cm}=0.\text{452}\times
\text{1}{{0}^{\text{3}}}\text{cm}\]
\[\text{x}+\text{y}=\left( \text{6}\text{.75}\times
\text{1}{{0}^{\text{3}}}+0.\text{452}\times \text{1}{{0}^{\text{3}}}
\right)\text{cm}=\text{7}\text{.2}0\text{2}\times
\text{1}{{0}^{\text{3}}}\text{cm}\]
= \[\text{7}\text{.2}0\times \text{1}{{0}^{\text{3}}}\text{cm}\] (upto
two places of decimal).
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