Answer:
No, it
is not true as their dimensions are different.
\[Energy=\left[
{{M}^{1}}{{L}^{2}}{{T}^{-2}} \right]\]
Young's modulus = \[\frac{F/a}{\Delta
L/L}=\frac{ML{{T}^{-2}}/{{L}^{2}}}{1}=\left[ {{M}^{1}}{{L}^{-1}}{{T}^{-2}}
\right]\]
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