Answer:
Length (l)
Least count
\[\left( \Delta l \right)\]
Relativeerro
\[\left( \frac{\Delta l}{l} \right)\]
(i)
4.0 M
0.01mm
\[\frac{0.01}{4.00}=\text{2}.\text{5}\times
\text{1}{{0}^{-\text{3}}}\]
(ii)
4.0 M
0.01 cm
\[\frac{0.01}{4.00}=\text{2}.\text{5}\times
\text{1}{{0}^{-\text{3}}}\]
(iii)
4.0
M
0.01 m
\[\frac{0.01}{4.00}=\text{2}.\text{5}\times
\text{1}{{0}^{-\text{3}}}\]
(iv)
40.00
M
0.01m
\[\frac{0.01}{40.00}=\text{2}.\text{5}\times
\text{1}{{0}^{-4}}\]
As relative error in measurement of 40.00 m is minimum, therefore,
it is most accurate measurement. However, the least count of measuring
instrument is minimum in case (i) being equal to 0.01 mm. Therefore,
measurement (i) is most precise.
You need to login to perform this action.
You will be redirected in
3 sec
