question_answer

If \[{{\in }_{0}}\] is electric permittivity of free space and E is electric field, then show that \[{{\in }_{0}}{{E}^{2}}\] has the dimensions of pressure.

Answer:

                It is known that \[\frac{1}{2}{{\in }_{0}}{{E}^{2}}\] represents energy density, i.e., energy per unit volume i.e. dimensions of \[{{\in }_{0}}{{E}^{2}}=\frac{energy}{volume}=\frac{force\,\times dis\tan ce}{area\times length}=\frac{force}{area}=pressure\]