11th Class Physics Physical World / भौतिक जगत Question Bank 11th CBSE Physics Mathematical Tools, Units & Dimensions

  • question_answer
    Match the physical quantities with dimensions expressed in disarray. (i) Angular momentum                                                  (i) \[\left[ {{M}^{-1}}{{L}^{3}}{{T}^{-2}} \right]\] (ii) Latent heat                                                                  (ii) \[\left[ {{M}^{1}}{{L}^{3}}{{T}^{-3}}{{A}^{-2}} \right]\] (iii) Specific heat                                                               (iii) \[\left[ {{M}^{0}}{{L}^{2}}{{T}^{-2}} \right]\] (iv) Joule's mechanical equivalent of heat             (iv) \[\left[ {{M}^{0}}{{L}^{2}}{{T}^{-2}}{{K}^{-1}} \right]\] (v) Resistivity                                                                     (v) \[\left[ {{M}^{0}}{{L}^{0}}{{T}^{0}} \right]\] (vi) Gravitational Constant                                           (vi) \[\left[ {{M}^{1}}{{L}^{2}}{{T}^{-1}} \right]\]

    Answer:

                     (i) Angular momentum = \[\left[ {{M}^{1}}{{L}^{2}}{{T}^{-1}} \right]\]    (ii) Latent heat = \[\left[ {{M}^{0}}{{L}^{2}}{{T}^{-2}} \right]\] (iii) Specific heat =\[\left[ {{M}^{0}}{{L}^{2}}{{T}^{-2}}{{K}^{-1}} \right]\]                (iv) Joule's mechanical equivalent of heat = \[\left[ {{M}^{0}}{{L}^{0}}{{T}^{0}} \right]\] (v)Resistivity =  \[\left[ {{M}^{1}}{{L}^{3}}{{T}^{-3}}{{A}^{-2}} \right]\]                    (vi) Gravitational constant = \[\left[ {{M}^{-1}}{{L}^{3}}{{T}^{-2}} \right]\]


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