11th Class Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank 11th CBSE Chemistry Thermodynamics

  • question_answer
    Find out (i) Heat of formation of \[C{{H}_{4}}\] in terms of \[\Delta {{H}_{1}},\,\Delta {{H}_{2}}\] etc. (ii) Heat of sublimation of \[{{C}_{graphite}}\] in terms of \[\Delta {{H}_{1}},\,\Delta {{H}_{2}}\] etc. (iii) Heat of dissociation of \[{{H}_{2}}\] in terms of \[\Delta {{H}_{1}},\,\Delta {{H}_{2}}\] etc. 

    Answer:

                    From the given diagram, (i) Heat of formation of \[C{{H}_{4}}=\frac{\Delta {{H}_{3}}}{2}\,\] or \[=\frac{\Delta {{H}_{1}}+\Delta {{H}_{2}}+\Delta {{H}_{4}}}{2}\] (ii) Heat of sublimation of \[{{C}_{graphite}}\,i.e.,\,\,{{C}_{graphite\,(s)}}\,\xrightarrow{\,}\,{{C}_{graphite\,(g)}}=\frac{\Delta {{H}_{1}}}{2}\] (iii) Heat of dissociation of \[{{H}_{2}},\,i.e.,\,{{H}_{2}}(g)\,\to 2\,H(g)\,=\frac{\Delta {{H}_{2}}}{4}\]


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