Answer:
\[P\times
V=\frac{\text{Force}}{\text{Area}}\times
\text{Volume}=\frac{\text{Force}\,\times
{{\text{(Length)}}^{\text{3}}}}{{{\text{(Length)}}^{\text{2}}}}=\] \[\text{Force}\times
\text{Length}=\text{work}\], which has same units as that of energy.
1 L atm = (1 \[d{{m}^{3}}\]) (101325 N \[{{m}^{-2}}\]) = (\[{{10}^{-3}}{{m}^{3}}\])
(101325 N \[{{m}^{-2}}\]) = 101.325 N m = 101.325 J.
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