Answer:
In \[AlC{{l}_{3}},\] Al has only six
electrons in the valence shell. Therefore, it needs two more electrons to
complete its octet. To do so, it accepts a lone pair of electrons from the Cl
atom of another \[AlC{{l}_{3}}\] molecule as shown in Fig. 11.2, page 11/10. As
a result, \[AlC{{l}_{3}}\] exists as a dimer.
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