Answer:
Boron atom being small in size is
unable to accommodate four large sized halogen atoms (except F) around it.
However, because of bigger size, Al can easily accommodate four big sized Cl
atoms around it. Since in\[AlC{{l}_{3}},\] there are only six electrons around
Al atom, therefore, it completes its octet by accepting a lone pair of
electrons from Cl atom of another \[AlC{{l}_{3}}\] molecule. As a result, \[AlC{{l}_{3}}\]
exists as a chlorine bridged dimeric structure. Refer to Fig. 11.2, page 11/10.
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