question_answer

How many electrons is sulphur (Z = 16) can have \[n+l=3\]?

Answer:

                Electronic configuration of \[_{16}S=1\,{{s}^{2}}\,2\,{{s}^{2}}\,2\,{{p}^{6}}\,3\,{{s}^{2}}\,3\,{{p}^{4}}\] For \[1\,{{s}^{2}},\,n+l=1\,+0=1\] For \[2\,{{s}^{2}},\,n+l=2+0=2\] For \[2{{p}^{6}},\,n+l=2+1=3\] For \[3\,{{s}^{2}},\,n+l=3+0=3\] For \[3{{p}^{4}},\,n+l=3+1=4\] Thus, \[n+l=3\] for\[2{{p}^{6}}\] and \[3{{s}^{2}}\] electrons i.e., for 8 electrons.