question_answer

What is the angular momentum of an electron in (i) 2 s orbital (ii) 4 f orbital?

Answer:

                Angular momentum of electron in any orbital\[=\sqrt{l(l+1)}=\frac{h}{2\pi }\] \[\therefore \] For 2 s orbital, \[l=0,\] \[\therefore \] angular momentum \[=\sqrt{0(0+1)}\,\frac{h}{2\pi }=0\] For \[4f\] orbital, \[l=3,\] \[\therefore \] angular momentum\[=\sqrt{3(3+1)}\,\frac{h}{2\pi }=2\sqrt{3}\,\frac{h}{2\pi }=\sqrt{3}\,\frac{h}{\pi }\]