question_answer

Two bulbs \[{{B}_{1}}\] and \[{{B}_{2}}\] of equal capacity contain 10g oxygen \[({{O}_{2}})\] and ozone \[({{O}_{3}})\] respectively. Which bulb will have greater number of O-atoms and which will have greater number of molecules?

Answer:

                \[10\,g\,{{O}_{2}}=\frac{10}{32}\,\text{mole}\]\[=\frac{10}{32}\times 6.02\times {{10}^{23}}\]molecules\[=1\cdot 88\times {{10}^{23}}\] molecules              \[=2\times 1.88\times {{10}^{23}}\] atoms\[=3.76\times {{10}^{23}}\] atoms \[10g\,{{O}_{3}}=\frac{10}{48}\]mole\[=\frac{10}{48}\times 6.02\times {{10}^{23}}\]  molecules\[=1.254\times {{10}^{23}}\]molecules \[=3\times 1.254\times {{10}^{23}}\]atoms \[=3.76\times {{10}^{23}}\]  atoms Thus, both contain the same number of atoms but bulb \[{{B}_{1}}\] contains more number of molecules.