• # question_answer Out of ${{(HS{{O}_{4}})}^{-}}$and ${{(HS{{O}_{3}})}^{-}}$ which is a stronger base?

The anions (conjugate bases) are formed from the corresponding acids as follows: ${{H}_{2}}\overset{+6}{\mathop{S}}\,{{O}_{4}}\rightleftharpoons {{(HS{{O}_{4}})}^{-}}+{{H}^{+}}$           $H\overset{+5}{\mathop{S}}\,O_{3}^{-}\rightleftharpoons SO_{4}^{2-}+{{H}^{+}}$ Please note that smaller the oxidation number of the atom, stronger will be corresponding conjugate base. Therefore,$HSO_{3}^{-}$ is a stronger base.