question_answer

Determine the oxidation number of the element in the bold in the following species (i)\[Si{{H}_{4}}\]                (ii)\[B{{H}_{3}}\]                               (iii)\[B{{F}_{3}}\]                (iv)\[{{S}_{2}}O{{_{3}^{{}}}^{2-}}\]           (v)\[BrO{{_{4}^{{}}}^{-}}\]     (vi)\[HP{{O}_{4}}^{2-}\]               

Answer:

(i)	\[Si{{H}_{4}}\]	: \[\overset{x}{\mathop{S}}\,i{{\overset{+1}{\mathop{H}}\,}_{4}}\]	\[x+4(+1)=0\]	or\[x=-4\]
(ii)	\[B{{H}_{3}}\]	\[:\overset{x}{\mathop{B}}\,{{\overset{+1}{\mathop{H}}\,}_{3}}\]	\[x+3(+1)=0\]	or \[x=-3\]
(iii)	\[B{{F}_{3}}\]	:\[\overset{x}{\mathop{B}}\,{{\overset{-1}{\mathop{F}}\,}_{3}}\]	\[x+3(-1)=0\]	or \[x=+3\]
(iv)	\[{{S}_{2}}{{O}_{3}}^{2-}\]	\[:{{\overset{x}{\mathop{S}}\,}_{2}}{{\overset{-2}{\mathop{O}}\,}_{3}}\]	\[2(x)+3(-2)=-2\]	or \[x=+2\]
(v)	\[BrO{{_{4}^{{}}}^{-}}\]	\[:\overset{x}{\mathop{B}}\,r\,{{\overset{-2}{\mathop{O}}\,}_{4}}\]	\[x+4(-2)=-1\]	or \[x=+7\]
(vi)	\[HP{{O}_{4}}^{2-}\]	: \[\overset{+1}{\mathop{H}}\,\overset{x}{\mathop{P}}\,\,{{\overset{-2}{\mathop{O}}\,}_{4}}\]	\[(+1)+x+4(-2)=-2\]	or \[x=+5\]