• question_answer ) Higher alkyl substituted alkene is formed in greater proportion than the lower alkyl substituted alkene. Justify.

In alkyl substituted alkene, the $\alpha$-hydrogen atoms of the methyl group are involved in the hyper conjugation with the pi$(\pi )$ electron pair of the double bond. As a result, the stability of alkene increases. Greater the number of such groups more will be the stability of alkene. Thus, the relative order of stability of the following alkenes is: $\underset{\text{But-2-ene}}{\mathop{C{{H}_{3}}-CH}}\,=CH-C{{H}_{3}}>\underset{\text{Propene}}{\mathop{C{{H}_{3}}}}\,-CH$$=C{{H}_{2}}>\underset{\text{Ethene}}{\mathop{C{{H}_{2}}}}\,=C{{H}_{2}}$