question_answer

For an aqueous solution of \[N{{H}_{4}}Cl,\] prove that \[[{{H}_{3}}{{O}^{+}}]\,=\sqrt{{{K}_{h}}C}\].

Answer:

                Refer to page 7/136. For salt of strong acid and weak base, \[[{{H}_{3}}{{O}^{+}}]\,=\sqrt{\frac{{{K}_{w}}C}{{{K}_{b}}}}\] Substituting \[\frac{{{K}_{w}}}{{{K}_{b}}}\,={{K}_{h}},\] we get \[[{{H}_{3}}{{O}^{+}}]\,=\sqrt{{{K}_{h}}C}\]