question_answer

If concentrations are expressed in moles \[{{L}^{-1}}\] and pressures in atmospheres, what is the ratio of \[{{K}_{p}}\] to \[{{K}_{c}}\] for the reaction : \[2S{{O}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2S{{O}_{3}}(g)\]at \[25{}^\circ C\]?

Answer:

                \[\Delta \,{{n}_{g}}={{n}_{p}}-{{n}_{r}}=-1\]. Hence, \[{{K}_{p}}={{K}_{c}}{{(RT)}^{-1}}\] or \[{{K}_{p}}/{{K}_{c}}=1/RT=\frac{1}{0.0821\times 298}=0.04\]