11th Class Chemistry Equilibrium Question Bank 11th CBSE Chemistry Ionic Equilibrium

  • question_answer \[S{{O}_{3}}\] is an acidic oxide while \[N{{a}_{2}}O\]  is basic in nature. Support the same with the help of examples.

    Answer:

                    (i) \[S{{O}_{3}}\] is an acidic oxide because it dissolves in water to form \[{{H}_{2}}S{{O}_{4}}\]  (acid) and also forms a salt with \[NaOH\] (base). \[S{{O}_{3}}+{{H}_{2}}O\xrightarrow{\,}{{H}_{2}}S{{O}_{4}}\] \[S{{O}_{3}}+2NaOH\xrightarrow{\,}N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O\] (ii) \[N{{a}_{2}}O\] is basic oxide because it dissolves in water to form \[NaOH\](base) and also forms a salt with \[HCl\] (acid) \[N{{a}_{2}}O+{{H}_{2}}O\xrightarrow{\,}2NaOH\] \[N{{a}_{2}}O+2HCl\xrightarrow{\,}\,2NaCl+{{H}_{2}}O\]


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