• # question_answer $S{{O}_{3}}$ is an acidic oxide while $N{{a}_{2}}O$  is basic in nature. Support the same with the help of examples.

(i) $S{{O}_{3}}$ is an acidic oxide because it dissolves in water to form ${{H}_{2}}S{{O}_{4}}$  (acid) and also forms a salt with $NaOH$ (base). $S{{O}_{3}}+{{H}_{2}}O\xrightarrow{\,}{{H}_{2}}S{{O}_{4}}$ $S{{O}_{3}}+2NaOH\xrightarrow{\,}N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O$ (ii) $N{{a}_{2}}O$ is basic oxide because it dissolves in water to form $NaOH$(base) and also forms a salt with $HCl$ (acid) $N{{a}_{2}}O+{{H}_{2}}O\xrightarrow{\,}2NaOH$ $N{{a}_{2}}O+2HCl\xrightarrow{\,}\,2NaCl+{{H}_{2}}O$