Answer:
(i) \[S{{O}_{3}}\] is an acidic
oxide because it dissolves in water to form \[{{H}_{2}}S{{O}_{4}}\] (acid) and
also forms a salt with \[NaOH\] (base).
\[S{{O}_{3}}+{{H}_{2}}O\xrightarrow{\,}{{H}_{2}}S{{O}_{4}}\]
\[S{{O}_{3}}+2NaOH\xrightarrow{\,}N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O\]
(ii) \[N{{a}_{2}}O\] is basic oxide
because it dissolves in water to form \[NaOH\](base) and also forms a salt with
\[HCl\] (acid)
\[N{{a}_{2}}O+{{H}_{2}}O\xrightarrow{\,}2NaOH\]
\[N{{a}_{2}}O+2HCl\xrightarrow{\,}\,2NaCl+{{H}_{2}}O\]
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