(b)\[C{{H}_{3}}-C\equiv
C-C{{H}_{3}}\xrightarrow{\text{Na/liq}\,\text{N}{{\text{H}}_{\text{3}}}}\]
Answer:
(a) Refer to 'Competition Focus',
page 13/149. (b) Refer to sec. 13.7.8, page 13/57.
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