Answer:
The structures of the products of ozonolysis are:
Since, the total number of carbon atoms of the two products is 11 (4 + 7) while the MF of the conjugated diene is \[{{C}_{13}}{{H}_{22}},\] therefore, the ozonolysis must have also produced another two carbon product. Further since the given compound \[({{C}_{13}}{{H}_{22}})\] is an alkadiene, therefore, this two carbon product must be glyoxal, \[O=CH-CH=O\]. Replace the oxygen atoms from these three products by double bonds, the structure of the alkadiene is
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