Answer:
\[\underset{\text{Ethyne}}{\mathop{HC\equiv
CH}}\,\xrightarrow[196\,K]{Na,\,\,N{{H}_{3}}(l)}\,HC\equiv
{{C}^{-}}\,N{{a}^{+}}\]\[\xrightarrow[-NaI]{C{{H}_{3}}I}\,\underset{\Pr
\text{opyne}}{\mathop{C{{H}_{3}}-C\equiv
CH}}\,\xrightarrow[196\,K]{Na,\,N{{H}_{3}}(l)}\,\underset{\text{Sod}\text{.}\,\,\text{propynide}}{\mathop{C{{H}_{3}}-C\equiv
{{C}^{-}}N{{a}^{+}}}}\,\]
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