Answer:
E.C. of C-atom is \[1{{s}^{2}}2{{s}^{2}}2{{p}^{2}}\]
and E.C. of B-atom is \[1{{s}^{2}}2{{s}^{2}}2{{p}^{1}}\]. The first electron to
be removed in both cases is from a 2p-orbital but nuclear charge of C is more
than that of B. Therefore, the \[{{\Delta }_{i}}{{H}_{1}}\] of C is greater than
that of B. After the removal of first electron, the second electron to be
removed from C-atom is froma 2p-orbital whereas that from B-atom is from a 2s
orbital. Since a s-orbital is more penetrating and hence is more strongly attracted
by the nucleus than a p-orbital, therefore, \[{{\Delta }_{i}}{{H}_{2}}\] of B
is higher than that of C.
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