11th Class Chemistry Classification of Elements and Periodicity in Properties / तत्त्वों का वर्गीकरण एवं गुणों में आवर्ति Question Bank 11th CBSE Chemistry Classification of Elements and Periodicity in Properties

  • question_answer
    The element 119 has not been discovered. What could be the IUPAC name and symbol for this element? On the basis of the periodic table, predict the electronic configuration of this element and also the formula of its most stable chloride and oxide.

    Answer:

                    (i) The roots for 1 and 9 are un and enn respectively. Therefore, the name for the element with Z = 119 is un + un + enn + ium = ununennium and its symbol is Uue. (ii) The maximum number of elements which can be accommodated in the present set up of the long form of the periodic table = 118 (For details refer to Q. 2, page 3/91). Since this last element would be an inert gas, therefore, the element with Z = 119 will be an alkali metal and hence its outer electronic configuration will be \[8{{s}^{1}}\] or its complete electronic configuration will be\[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}\]\[4{{s}^{2}}4{{p}^{6}}4{{d}^{10}}4{{f}^{14}}5{{s}^{2}}\] \[5{{p}^{6}}5{{d}^{10}}5{{f}^{14}}6{{s}^{2}}\,6{{p}^{6}}\,6{{d}^{10}}\]\[7{{s}^{2}}7{{p}^{6}}\,8{{s}^{1}}\]. (iii) Since the element with Z = 119 will be an alkali metal, therefore, formula of its chloride will be MCl and that of its stable oxide will be bold \[{{M}_{2}}O\] where M is the alkali metal.


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