• # question_answer Explain why${{N}_{2}}$ has  greater bond dissociation energy than $N_{2}^{+}$ whereas $O_{2}^{+}$ has greater bond dissociation energy than ${{O}_{2}}$.

B.O. of ${{N}_{2}}(3)>B.O.$ of $N_{2}^{+}\,(2\cdot 5)\,$ but B.O. of $O_{2}^{+}\,(2\cdot 5)>B.O.$ of ${{O}_{2}}\,(2)$. Greater the bond order, greater is the bond dissociation energy.