11th Class Chemistry Chemical Bonding and Molecular Structure Question Bank 11th CBSE Chemistry Chemical Bonding and Molecular Structure

  • question_answer Explain why\[{{N}_{2}}\] has  greater bond dissociation energy than \[N_{2}^{+}\] whereas \[O_{2}^{+}\] has greater bond dissociation energy than \[{{O}_{2}}\].

    Answer:

                    B.O. of \[{{N}_{2}}(3)>B.O.\] of \[N_{2}^{+}\,(2\cdot 5)\,\] but B.O. of \[O_{2}^{+}\,(2\cdot 5)>B.O.\] of \[{{O}_{2}}\,(2)\]. Greater the bond order, greater is the bond dissociation energy.


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