Answer:
Hybridisation:\[C-1=sp,\,C-2=s{{p}^{3}},\,C-3=s{{p}^{2}}\]
.
Hence, s-character will be in the order:
\[\underset{(50%)}{\mathop{C-1}}\,\,\,\,>\,\,\,\underset{(33%)}{\mathop{C-3}}\,\,\,\,>\,\,\underset{(25%)}{\mathop{C-2}}\,\].
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