• # question_answer In the following molecule: $C{{H}_{3}}-C\equiv \overset{1}{\mathop{C}}\,-\overset{2}{\mathop{C}}\,{{H}_{2}}-\overset{\begin{smallmatrix} O \\ 3|| \end{smallmatrix}}{\mathop{C}}\,-OH$ arrange the carbon atoms numbered$C-1,\,C-2$  and$C-3$ in the decreasing order of s-character.

Hybridisation:$C-1=sp,\,C-2=s{{p}^{3}},\,C-3=s{{p}^{2}}$ . Hence, s-character will be in the order: $\underset{(50%)}{\mathop{C-1}}\,\,\,\,>\,\,\,\underset{(33%)}{\mathop{C-3}}\,\,\,\,>\,\,\underset{(25%)}{\mathop{C-2}}\,$.