• # question_answer Which is more polar $-C{{O}_{2}}$ or ${{N}_{2}}O$? Give reason.

${{N}_{2}}O$ is more polar than $C{{O}_{2}}$. This is because $C{{O}_{2}}$ is linear and symmetrical. Its net dipole moment is zero $(O\overset{\leftarrow }{\mathop{=}}\,C\overset{\to }{\mathop{=}}\,O).$${{N}_{2}}O$  is linear but unsymmetrical. It is considered as a resonance hybrid of the following two structures: It has a net dipole moment of 0.116 D.