11th Class Chemistry Chemical Bonding and Molecular Structure Question Bank 11th CBSE Chemistry Chemical Bonding and Molecular Structure

  • question_answer
    Arrange the following in order of decreasing bond angle, giving reason : \[N{{O}_{2}},\,NO_{2}^{+},\,NO_{2}^{-}\]

    Answer:

                    \[NO_{2}^{+}>N{{O}_{2}}>NO_{2}^{-}\]. This is because \[NO_{2}^{+}\] has no lone pair of electrons (i.e. has only bond pairs on two sides) and hence it is linear. \[N{{O}_{2}}\] has one unshared electron while \[NO_{2}^{-}\] has one unshared electron pair. There are greater repulsions on \[N-O\] bonds in case of \[NO_{2}^{-}\] than in case of \[N{{O}_{2}}\].


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