Answer:
The species will be planar if the central atom is \[s{{p}^{2}}\] hybridised. Let us calculate the hybridisation in all these species.
(i)\[NH_{4}^{+}:\]\[H=1/2[5+4-1+0]=4\] (\[s{{p}^{3}}\]-non-planar)
(ii)\[CH_{3}^{+}:\]\[H=1/2[4+3-1+0]\,=6/2=3\] (\[s{{p}^{2}}\]- planar)
(iii)\[S{{F}_{4}}:\]\[H=1/2[6+4-0+0]=10/2=5\] (\[s{{p}^{3}}d\]- non-planar)
(iv)\[O{{F}_{2}}:\]\[H=1/2[6+2-0+0]=8/2=4\] (\[s{{p}^{3}}\]- non-planar)
(v)\[{{H}_{2}}O:\,\]\[H=1/2[6+2-0+0]\,=8/2=4\] (\[s{{p}^{3}}\]-non-planar)
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