Answer:
\[{{N}_{2}}O\] is more polar than \[C{{O}_{2}}\].
This is because \[C{{O}_{2}}\] is linear and symmetrical. Its net dipole moment
is zero \[(O\overset{\leftarrow }{\mathop{=}}\,C\overset{\to
}{\mathop{=}}\,O).\]\[{{N}_{2}}O\] is linear but unsymmetrical. It is
considered as a resonance hybrid of the following two structures:
It has a net dipole moment of 0.116
D.
You need to login to perform this action.
You will be redirected in
3 sec