A) \[\pi \sqrt{3}\] done clear
B) \[\sqrt{3\pi }\] done clear
C) \[3\sqrt{\pi }\] done clear
D) \[3\pi \] done clear
View Solution play_arrowA) \[44\text{ }c{{m}^{2}}\] done clear
B) \[308\text{ }c{{m}^{2}}\] done clear
C) \[77\text{ }c{{m}^{2}}\] done clear
D) \[154\text{ }c{{m}^{2}}\] done clear
View Solution play_arrowA) \[91\text{ }c{{m}^{2}}\] done clear
B) \[95\,c{{m}^{2}}\] done clear
C) \[97\,c{{m}^{2}}\] done clear
D) \[88\,c{{m}^{2}}~\] done clear
View Solution play_arrowA) 4 cm done clear
B) 7 cm done clear
C) 11 cm done clear
D) 9 cm done clear
View Solution play_arrowA) 80 m done clear
B) 81 m done clear
C) 82 m done clear
D) 88 m done clear
View Solution play_arrowA) \[3.4\text{ }cm\] done clear
B) \[3.5\text{ }cm\] done clear
C) \[3.2\text{ }cm\] done clear
D) \[3.1\text{ }cm\] done clear
View Solution play_arrowA) \[30720.5\,c{{m}^{2}}\] done clear
B) \[31021.42\,c{{m}^{2}}\] done clear
C) \[30391.7\,c{{m}^{2}}\] done clear
D) \[30520.61\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[32.4\text{ }m\] done clear
B) \[36.4\text{ }m\] done clear
C) \[32.6\,m\] done clear
D) \[39.4\text{ }m\] done clear
View Solution play_arrowA) \[1125\text{ }c{{m}^{2}}\] done clear
B) \[1321\text{ }c{{m}^{2}}\] done clear
C) \[1210\,\,c{{m}^{2}}\] done clear
D) \[1225\,\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[6\sqrt{3}\] done clear
B) \[2\pi -6\sqrt{3}\] done clear
C) \[2\pi -3\sqrt{3}\] done clear
D) \[3\sqrt{3}\] done clear
View Solution play_arrowA) \[15.1\text{ }c{{m}^{2}}\] done clear
B) \[15.5\text{ }c{{m}^{2}}\] done clear
C) \[15.6\,c{{m}^{2}}\] done clear
D) \[15.9\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[8\,c{{m}^{2}}\] done clear
B) \[8\,\sqrt{\pi \,}c{{m}^{2}}\] done clear
C) \[16\,c{{m}^{2}}\] done clear
D) \[16\sqrt{\pi }\,c{{m}^{2}}\] done clear
View Solution play_arrowquestion_answer13) In the given figure, the area of the shaded region is ___.
A) \[3\pi \,c{{m}^{2}}\] done clear
B) \[6\pi \,c{{m}^{2}}\] done clear
C) \[9\pi \,c{{m}^{2}}\] done clear
D) \[7\pi \,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[55\,m\] done clear
B) \[110\,m\] done clear
C) \[220\text{ }m\] done clear
D) \[~230\text{ }m\] done clear
View Solution play_arrowA) \[70\text{ }m\] done clear
B) \[105\text{ }m\] done clear
C) \[88\text{ }m\] done clear
D) \[85\text{ }m\] done clear
View Solution play_arrowA) \[Rs.\,310.75\] done clear
B) \[Rs.\,308.91\] done clear
C) \[Rs.\,250.25\] done clear
D) \[Rs.\,360.82\] done clear
View Solution play_arrowA) 200 done clear
B) 210 done clear
C) 250 done clear
D) 240 done clear
View Solution play_arrowA) Rs.2671 done clear
B) Rs.4401 done clear
C) Rs.2512 done clear
D) Rs.3140 done clear
View Solution play_arrowA) 10 mins 42 sees done clear
B) 12 mins 35 sees done clear
C) 15 mins 42 sees done clear
D) 10 mins 35 sees done clear
View Solution play_arrowA) Rs.31425 done clear
B) Rs. 28260 done clear
C) Rs.352.40 done clear
D) Rs. 282.60 done clear
View Solution play_arrowA) \[\left\{ \frac{5\pi }{3}(5\sqrt{3}+1)-5\sqrt{3} \right\}\] done clear
B) \[\left\{ \frac{4\pi }{2}(4\sqrt{2}+1)-4\sqrt{2} \right\}\] done clear
C) \[\left\{ \frac{4\pi }{3}(4\sqrt{3}+1)-4\sqrt{2} \right\}\] done clear
D) \[\left\{ \frac{4\pi }{3}(4\sqrt{3}+1)-4\sqrt{3} \right\}\] done clear
View Solution play_arrowquestion_answer22) Match the shaded region given in Column-l with their areas in Column-ll.
Column-l | Column-II |
(P) | (i) \[262.50\text{ }c{{m}^{2}}\] |
(Q) | (ii) \[271.04\text{ }c{{m}^{2}}\] |
(R) | (iii) \[427.14\,\,c{{m}^{2}}\] |
A) (P) \[\to \](iii); (Q) \[\to \](ii); (R) \[\to \] (i) done clear
B) (P) \[\to \] (ii); (Q) \[\to \] (i); (R)\[\to \] (iii) done clear
C) (P) \[\to \] (ii); (Q) \[\to \] (iii); (R) \[\to \] (i) done clear
D) (P) \[\to \] (iii); (Q) \[\to \](i); (R) \[\to \] (ii) done clear
View Solution play_arrowA) \[12-4\sqrt{3}\] done clear
B) \[\frac{6-\sqrt{3}}{2}\] done clear
C) \[\frac{3-\sqrt{3}}{2}\] done clear
D) \[4\sqrt{3}-6\] done clear
View Solution play_arrowA) 7 sq. units done clear
B) 8 sq. units done clear
C) 5 sq. units done clear
D) 6 sq. units done clear
View Solution play_arrowquestion_answer25) In the given figure, ABCD is a square of side 10 cm. Find
(i) Area of inscribed circle |
(ii) Area of circumscribed circle |
(iii) Area of shaded region |
A)
(i) | (ii) | (iii) | |
\[\frac{1100}{7}c{{m}^{2}}\] | \[\frac{550}{7}c{{m}^{2}}\] | \[\frac{550}{7}c{{m}^{2}}\] |
B)
(i) | (ii) | (iii) | |
\[\frac{550}{7}c{{m}^{2}}\] | \[\frac{1100}{7}c{{m}^{2}}\] | \[\frac{550}{7}c{{m}^{2}}\] |
C)
(i) | (ii) | (iii) | |
\[\frac{550}{7}c{{m}^{2}}\] | \[\frac{550}{7}c{{m}^{2}}\] | \[\frac{1100}{7}c{{m}^{2}}\] |
D)
(i) | (ii) | (iii) | |
\[\frac{1100}{7}c{{m}^{2}}\] | \[\frac{1100}{7}c{{m}^{2}}\] | \[\frac{550}{7}c{{m}^{2}}\] |
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