Velocity at the Bottom of Rough Wedge
Category : JEE Main & Advanced
A body of mass m which is placed at the top of the wedge (of height h) starts moving downward on a rough inclined plane.
Loss of energy due to friction = FL (Work against friction)
PE at point A = mgh
KE at point B = \[\frac{1}{2}m{{u}^{2}}\]
By the law of conservation of energy
i.e. \[\frac{1}{2}m{{v}^{2}}=mgh-FL\]
\[v=\sqrt{\frac{2}{m}(mgh-FL)}\]
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