Motion of Blocks Connected by Mass Less String
Category : JEE Main & Advanced
| Condition | Free body diagram | Equation | Tension and acceleration |
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\[T={{m}_{1}}a\] | \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}}\] |
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\[F-T={{m}_{2}}a\] | \[T=\frac{{{m}_{1}}F}{{{m}_{1}}+{{m}_{2}}}\] | |
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\[F-T={{m}_{1}}a\] | \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}}\] |
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\[T={{m}_{2}}a\] | \[T=\frac{{{m}_{2}}F}{{{m}_{1}}+{{m}_{2}}}\] | |
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\[{{T}_{1}}={{m}_{1}}a\] | \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\] |
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\[{{T}_{2}}-{{T}_{1}}={{m}_{2}}a\] | \[{{T}_{1}}=\frac{{{m}_{1}}F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\] | |
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\[F-{{T}_{2}}={{m}_{3}}a\] | \[{{T}_{2}}=\frac{({{m}_{1}}+{{m}_{2}})F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\] | |
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\[F-{{T}_{1}}={{m}_{1}}a\] | \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}={{m}_{3}}}\] |
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\[{{T}_{1}}-{{T}_{2}}={{m}_{2}}a\] | \[{{T}_{1}}=\frac{({{m}_{2}}+{{m}_{3}})F}{{{m}_{1}}+{{m}_{2}}={{m}_{3}}}\] | |
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\[{{T}_{2}}={{m}_{3}}a\] | \[{{T}_{2}}=\frac{{{m}_{3}}F}{{{m}_{1}}+{{m}_{2}}={{m}_{3}}}\] |
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