JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Cell in Various Positions

Cell in Various Positions

Category : JEE Main & Advanced

(1) Closed circuit : Cell supplies a constant current in the circuit.

(i) Current given by the cell \[i=\frac{E}{R+r}\]

(ii) Potential difference across the resistance \[V=iR\]

(iii) Potential drop inside the cell \[=ir\]

(iv) Equation of cell \[E=V+ir\]\[(E>V)\]

(v) Internal resistance of the cell \[r=\left( \frac{E}{V}-1 \right)\,\cdot R\]

(vi) Power dissipated in external resistance (load)

\[P=Vi={{i}^{2}}R=\frac{{{V}^{2}}}{R}={{\left( \frac{E}{R+r} \right)}^{2}}.R\]

Power delivered will be maximum when \[R=r\] so \[{{P}_{\max }}=\frac{{{E}^{2}}}{4r}\].

This statement in generalised from is called "maximum power transfer theorem".

(vii) When the cell is being charged i.e. current is given to the cell then \[E=V-ir\] and \[E<V\].

(2) Open circuit : When no current is taken from the cell  it is said to be in open circuit

(i) Current through the circuit \[i=0\]

(ii) Potential difference between A and B, \[{{V}_{AB}}=E\]

(iii) Potential difference between C and D, \[{{V}_{CD}}=0\]

(3) Short circuit : If two terminals of cell are join together by a thick conducting wire

(i) Maximum current (called short circuit current) flows momentarily \[{{i}_{sc}}=\frac{E}{r}\]

(ii) Potential difference V = 0

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