# JEE Main & Advanced Physics Simple Harmonic Motion Displacement in S.H.M.

Displacement in S.H.M.

Category : JEE Main & Advanced

(1) The displacement of a particle executing S.H.M. at an instant is defined as the distance of particle from the mean position at that instant.

(2) Simple harmonic motion is also defined as the projection of uniform circular motion on any diameter of circle of reference.

(3) If the projection is taken on y-axis. then from the figure

$y=a\sin \omega \,t$$=a\sin \frac{2\pi }{T}t$$=a\sin 2\pi \,n\,t$$=a\sin (\omega \,t\pm \varphi )$

(i) $y=a\sin \omega \,t$ when the time is noted from the instant when the vibrating particle is at mean position.

(ii) $y=a\cos \omega \,t$ when the time is noted from the instant when the vibrating particle is at extreme position.

(iii) $y=a\sin (\omega \,t\pm \varphi )$ when the vibrating particle is f phase leading or lagging from the mean position.

(4) If the projection of P is taken on X-axis then equations of S.H.M. can be given as $x=a\cos \,(\omega \,t\pm \varphi )$$=a\cos \,\left( \frac{2\pi }{T}t\pm \varphi \right)$$=a\cos \,(2\pi n\,t\pm \varphi )$

(5) Direction of displacement is always away from the equilibrium position, particle either is moving away from or is coming towards the equilibrium position.

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