Velocitytime Graph
Category : JEE Main & Advanced
The graph is plotted by taking time t along xaxis and velocity of the particle on yaxis.
Calculation of Distance and displacement : The area covered between the velocity time graph and time axis gives the displacement and distance travelled by the body for a given time interval.
Total distance \[=\,{{A}_{1}}\,+\,{{A}_{2}}\,+\,{{A}_{3}}\,\]
= Addition of modulus of different area. i.e. \[s\,=\,\int{\upsilon \,dt}\]
Total displacement \[={{A}_{1}}+{{A}_{2}}+{{A}_{3}}\]
= Addition of different area considering their sign.
i.e. \[r\,=\,\int{\upsilon \,dt}\]
Area above time axis is taken as positive, while area below time axis is taken as negative
here \[{{A}_{1}}\] and \[{{A}_{2}}\] are area of triangle 1 and 2 respectively and \[{{A}_{3}}\] is the area of trapezium
Calculation of Acceleration : Let AB is a velocitytime graph for any moving particle
As Acceleration = \[\frac{\text{Change in velocity}}{\text{Time taken}}\]
\[=\frac{{{v}_{2}}{{v}_{1}}}{{{t}_{2}}{{t}_{1}}}\] ...(i)
From triangle ABC, \[\tan \theta =\frac{BC}{AC}=\frac{AD}{AC}\]
\[=\frac{{{v}_{2}}{{v}_{1}}}{{{t}_{2}}{{t}_{1}}}\] ...(ii)
By comparing (i) and (ii)
Acceleration (a) = \[\tan \theta \]
It is clear that slope of tangent on velocitytime graph represents the acceleration of the particle.
Various velocity time graphs and their interpretation
\[\theta ={{0}^{o}},\,\,a=0,\,\,\upsilon =\] constant i.e., line parallel to time axis represents that the particle is moving with constant velocity. 

\[\theta ={{0}^{o}},\,\,a=\infty ,\,\,\upsilon =\] increasing i.e., line perpendicular to time axis represents that the particle is increasing its velocity, but time does not change. It means the particle possesses infinite acceleration. Practically it is not possible. 

\[\theta =\] constant, so a = constant and \[\upsilon \] is increasing uniformly with time i.e., line with constant slope represents uniform acceleration of the particle. 

\[\theta \] increasing so acceleration increasing i.e., line bending towards velocity axis represent the increasing acceleration in the body. 

\[\theta \] decreasing so acceleration decreasing i.e. line bending towards time axis represents the decreasing acceleration in the body 

Positive constant acceleration because \[\theta \] is constant and \[<{{90}^{o}}\] but initial velocity of the particle is negative.  
Positive constant acceleration because \[\theta \] is constant and \[<{{90}^{o}}\] but initial velocity of particle is positive.  
Negative constant acceleration because \[\theta \] is constant and \[>{{90}^{o}}\] but initial velocity of the particle is positive.  
Negative constant acceleration because \[\theta \] is constant and \[>{{90}^{o}}\] but initial velocity of the particle is zero.  
Negative constant acceleration because \[\theta \] is constant and \[>{{90}^{o}}\] but initial velocity of the particle is negative. 
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