Combination of Bulbs
Category : JEE Main & Advanced
(1) Series combination
(i) Total power consumed \[\frac{1}{{{P}_{total}}}=\frac{1}{{{P}_{1}}}+\frac{1}{{{P}_{2}}}+......\]
(ii) If \['n'\] bulbs are identical, \[{{P}_{total}}=\frac{P}{N}\]
(iii) \[{{P}_{consumed}}\,(\text{Brightness)}\propto V\propto R\propto \frac{1}{{{P}_{rated}}}\] i.e. in series combination bulb of lesser wattage will give more bright light and p.d. appeared across it will be more.
(2) Parallel combination
(i) Total power consumed \[{{P}_{total}}={{P}_{1}}+{{P}_{2}}+{{P}_{3}}......+{{P}_{n}}\]
(ii) If \['n'\] identical bulbs are in parallel. \[{{P}_{total}}=nP\]
(iii) \[{{P}_{consumed}}\,(\text{Brightness)}\propto {{P}_{R}}\propto i\propto \frac{1}{R}\] i.e. in parallel combination, bulb of greater wattage will give more bright light and more current will pass through it.
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