Equation of The Chord Joining Two Points on an Ellipse
Category : JEE Main & Advanced
The equation of the chord joining two points having eccentric angles \[\theta \] and \[\varphi \] on the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] is
\[\frac{x}{a}\cos \left( \frac{\theta +\varphi }{2} \right)+\frac{y}{b}\sin \left( \frac{\theta +\varphi }{2} \right)=\cos \left( \frac{\theta -\varphi }{2} \right)\].
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