Answer:
(a) \[{{x}^{\text{o}}}+{{125}^{\text{o}}}+{{125}^{\text{o}}}={{360}^{\text{o}}}\]. | \[\because \] The sum of the measures of the exterior angles of any polygon is \[{{360}^{o}}\] \[\Rightarrow \] \[x+{{250}^{\text{o}}}={{360}^{\text{o}}}\] \[\Rightarrow \] \[x={{360}^{\text{o}}}-{{250}^{\text{o}}}\] \[\Rightarrow \] \[x={{110}^{\text{o}}}\] (b) \[x+{{70}^{\text{o}}}+{{60}^{\text{o}}}+({{90}^{\text{o}}}+{{90}^{\text{o}}})={{360}^{\text{o}}}\]. | \[\because \] The sum of the measures of the exterior angles of any polygon is\[{{360}^{o}}\]. \[\Rightarrow \] \[x+{{310}^{\text{o}}}={{360}^{\text{o}}}\] \[\Rightarrow \] \[x={{360}^{\text{o}}}-{{310}^{\text{o}}}\] \[\Rightarrow \] \[x={{50}^{\text{o}}}\].
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