8th Class Mathematics Squares and Square Roots

  • question_answer 25)
                    Find the least number which must be subtracted from each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (i) 402                                    (ii) 1989                (iii) 3250                               (iv) 825 (v) 4000

    Answer:

                    (i) 402 We have  
    2            0
    2 \[\overline{4}\]         \[\overline{02}\] ?4
    40                02               ?00
    0
    This shows that 202 is less than 402 by 2. This means, if we subtract the remainder from the number, we get a perfect square. So, the required least number is 2. Therefore, the required perfect square is \[402-2=400\] Hence, \[\sqrt{400}=20\]. (ii) 1989 We have  
    4            4
    4 \[\overline{19}\]        \[\overline{89}\] ?16
    84 3             89 ?3            36
                    53
    This shows that \[{{44}^{2}}\] is less than 1989 by 53. This means that if we subtract the remainder from the number, we get a perfect square. So, the required least number is 53. Therefore, the required perfect square is 1989 - 53 = 1936. Hence, \[\sqrt{1936}=44\]. (iii) 3250 We have
    5            7
    5 \[\overline{32}\]        \[\overline{50}\] ?25
    107 7             50 ?7            49
                    1
    This shows that \[{{57}^{2}}\] is less than 3250 by 1. This means if we subtract the remainder from the number, we get a perfect square. So, the required least number is 1. Therefore, the required perfect square is \[3250-1=3249\] Hence, \[\sqrt{3249}\,=57\]. (iv) 825 We have
    2            8
    2 \[\overline{8}\]         \[\overline{25}\] ?4
    48 4            25 ?3           84
                   41
      This shows that 282 is less than 825 by 41. This means if we subtract the remainder from the number, we get a perfect square. So, the required least number is 41. Therefore, the required perfect square is \[825-41=784\] Hence, \[\sqrt{784}=28\]. (v) 4000 We have  
    63
    2 \[\overline{40}\]         \[\overline{00}\] ?36
    123 4            00 ?3          69
                   31
    This shows that 632 is less than 4000 by 31.                                  This means if we subtract the remainder from the number, we get a perfect square. So, the required least number is 31. Therefore, the required perfect square is \[4000-31=3969\]. Hence, \[\sqrt{3969}=63\].          


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