question_answer 8)

                Is \[\frac{8}{9}\] the multiplicative inverse of \[-1\frac{8}{9}\]? Why or why not?

Answer:

                \[-1\frac{1}{8}=-\frac{9}{8}\]                 Now, \[\frac{8}{9}\times \frac{-9}{8}=-1\ne 1\] So, No! \[\frac{8}{9}\] is not the multiplicative inverse of \[-1\,\frac{1}{8}\,\left( =-\frac{9}{8} \right)\] because the product of \[\frac{8}{9}\] and \[-1\,\frac{1}{8}\,\left( =-\,\frac{9}{8} \right)\] is not 1.