6th Class Mathematics Ratio and Proportion

  • question_answer 29) A truck requires 108 L of diesel for covering a distance of 594 km. How much diesel will be required by the truck to cover a distance of 1650 km?


                    Given, diesel required for 594 km = 108 L \[\therefore \]Diesel required for \[1km=\frac{108}{594}L=\frac{108\div 54}{594\div 54}=\frac{2}{11}L\] [\[\because \]HCF of 108 and \[594=3\times 3\times 3\times 2=54\]] \[\therefore \]Diesel required for \[1650km=\frac{2}{11}\times 1650L=2\times 150=300L\] \[\begin{align}   & 11)1650(150 \\  & \,\,\,\,\,\,\,\,\frac{11}{55} \\  & \,\,\,\,\,\,\,\,\frac{55}{\times } \\ \end{align}\] Hence, 300 L diesel required by the truck to cover 1650 km.

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