Answer:
To draw a circle, of diameter 6.1 cm, we use the following steps: Step I Draw a line segment \[{{l}_{2}}\] of length 6.1 cm. Step II With P as centre, using compasses, draw an arc of a circle (here, we can draw a circle also) with radius more than half of the length of \[S\to \]. Step III With the same radius and with Q as centre, draw another circle using compasses. Let it cut the previous circle at M and N. Step IV Now, join \[Y\to \] It cuts \[M\to \] at O. Therefore, \[E\to \] is the perpendicular bisector of \[T\to \] and O is the mid-point of \[R\to \]. Now, with O as centre and OP or OQ as radius, draw a circle. Thus, it is a circle whose diameter is the line segment \[S\xrightarrow[{}]{{}}\]. Hence, the circle PMQN is the required circle.
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