question_answer 45)

HCF of co-prime numbers 4 and 15 was found as follows by factorisation. \[4=2\times 2\] and \[15=3\times 5,\] since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

Answer:

No, the answer is not correct. Because 0 (zero) cannot be factor of any number. If there is no common factor means 1 is the common factor. \[\therefore \] HCF of 4 and 15 = 1