Answer:
Area of the rectangle \[\text{ABCD = l }\!\!\times\!\!\text{ b}\] \[\text{= 8 cm }\!\!\times\!\!\text{ 5 cm = 40 c}{{\text{m}}^{\text{2}}}\] Area of the rectangle PQRS \[=l\times b\] \[=\{8-(1.5+1.5)\}\text{ }cm\text{ }\times \text{ }\{5-(1.5+1.5)\}cm\] \[\text{= 5 cm }\!\!\times\!\!\text{ 2 cm = 10 c}{{\text{m}}^{\text{2}}}\] \[\therefore \] Total area of the margin = Area of the rectangle ABCD ? Area of the rectangle PQRS \[\text{= 40 c}{{\text{m}}^{\text{2}}}\text{-10 c}{{\text{m}}^{\text{2}}}\text{= 30 c}{{\text{m}}^{\text{2}}}\]
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