Answer:
Area of \[\text{ }\!\!\Delta\!\!\text{ ABC}\] \[\text{= }\frac{\text{1}}{\text{2}}\text{(bese }\!\!\times\!\!\text{ height)}\] \[\text{= }\frac{\text{1}}{\text{2}}\text{(BC }\!\!\times\!\!\text{ AD)}\] \[\text{=}\frac{\text{1}}{\text{2}}\text{(9 }\!\!\times\!\!\text{ 6) = 27 c}{{\text{m}}^{\text{2}}}\] Hence, Area of \[\text{ }\!\!\Delta\!\!\text{ ABC}\]is \[\text{27 c}{{\text{m}}^{2}}\] Again, Area of \[\Delta \Alpha \Beta C\] \[\text{= }\frac{\text{1}}{\text{2}}\text{(Base }\!\!\times\!\!\text{ height)}\] \[\text{= }\frac{\text{1}}{\text{2}}\text{(AB }\!\!\times\!\!\text{ CE)}\] \[\Rightarrow \] \[\text{27 = }\frac{\text{1}}{\text{2}}\text{(7}\text{.5 }\!\!\times\!\!\text{ CE)}\] \[\Rightarrow \] \[\text{CE = }\frac{\text{27 }\!\!\times\!\!\text{ 2}}{\text{7}\text{.5}}\text{=7}\text{.2 cm}\] Hence, the height from C to AB i.e., CE is 7.2 cm
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